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Message 20651
· CLubitz
· 7 Mar 2000 04:01:50
· Top

In a message dated 3/5/00 9:24:25 AM Eastern Standard Time,

pburrage@zoo.uvm.edu writes:

<< Whoops, am I mis-reading you, cece? I was taught that the distance from

the first man to the first woman was the same as the distance from the

first man to the third man.

Nevertheless, if you regard a grand circle as a rectangle instead of as a

circle (while being danced -- yes, I know it begins and ends as a square),

then, there is a problem of speeding upand slowing down. If it's a

circle, there is not. >>

hi priscilla --

you are right. the 1M to 1W distance is nominally 6' and the 1M to 2M is 3'

and another 3' to 3M. i said 3-4' just to allow a little leeway for the set

to elongate, as they often do. i was referring to the 1M-2M distance, not

the overall length of the set, which is twice that.

if we go with the 6x6 dimensions, and use the 1-1-2 phrasing, then 1M will

cross the set in 1 bar (6'); advance to 2W position in 1 bar (3', or half the

speed); then on to 3W position in 2 bars (again 3', but at 1/4 the speed of

his initial crossing.) that's where the factor of four comes from.

NOW, before anyone jumps on me, i realize that this strict interpretation of

time and distance is overly rigid, and that in practice, things even out a

lot. But that is not obvious to beginners, and they have a better shot at

doing it smoothly if they have an intellectual understanding of the need to

change their forward speed.

as far as considering it a circle goes (rather than a rectangle), if we

suppose that the corners of the 6'x6' square set become 4 points on a circle,

then the distances become the arcs of the circle, and there are 360/4 =90

degrees from one "corner" to another. Then there is still a factor of four

in speed, because 1M starts by covering 90 degrees in 1 bar; continues on the

next 45 degrees in 1 bar; and then does 45 degrees in 2 bars. when you say

there is no change in speed if you do it in a circle, you must be envisioning

a very large amount of "smoothing", which is certainly easier to do in a

circle than a rectangle.

Experienced dancers, like yourself, may achieve this smoothing so intuitively

that they don't realize it's happening, but the (admittedly) overly-strict

interpretation of the time and distance is still inescapable.

I think.

cece

Message 20658
· Priscilla M. Burrage
· 7 Mar 2000 12:57:56
· Top

On Mon, 6 Mar 2000 CLubitz@aol.com wrote:

> as far as considering it a circle goes (rather than a rectangle), if we

> suppose that the corners of the 6'x6' square set become 4 points on a circle,

> then the distances become the arcs of the circle, and there are 360/4 =90

> degrees from one "corner" to another. Then there is still a factor of four

> in speed, because 1M starts by covering 90 degrees in 1 bar; continues on the

> next 45 degrees in 1 bar; and then does 45 degrees in 2 bars. when you say

> there is no change in speed if you do it in a circle, you must be envisioning

> a very large amount of "smoothing", which is certainly easier to do in a

> circle than a rectangle.

Rule # 102.13: A chemical engineer should never argue math with a nuclear

physicist.

~~~~~~~~~~~~~~~~~

Priscilla Burrage Vermont US

(pburrage@zoo.uvm.edu)

Message 20718
· Leslie Henderson
· 13 Mar 2000 02:27:25
· Top

Is this one for the "omitted sections?"

--- "Priscilla M. Burrage" <pburrage@zoo.uvm.edu>

wrote:

> On Mon, 6 Mar 2000 CLubitz@aol.com wrote:

>

> > as far as considering it a circle goes (rather

> than a rectangle), if we

> > suppose that the corners of the 6'x6' square set

> become 4 points on a circle,

> > then the distances become the arcs of the circle,

> and there are 360/4 =90

> > degrees from one "corner" to another. Then there

> is still a factor of four

> > in speed, because 1M starts by covering 90 degrees

> in 1 bar; continues on the

> > next 45 degrees in 1 bar; and then does 45 degrees

> in 2 bars. when you say

> > there is no change in speed if you do it in a

> circle, you must be envisioning

> > a very large amount of "smoothing", which is

> certainly easier to do in a

> > circle than a rectangle.

>

> Rule # 102.13: A chemical engineer should never

> argue math with a nuclear

> physicist.

>

> ~~~~~~~~~~~~~~~~~

> Priscilla Burrage Vermont US

> (pburrage@zoo.uvm.edu)

>

>

>

>

=====

-----------------------------------------------Leslie Henderson, Bellingham WA USA

New web page address: http://www.wwu.edu/~henderl

Skagit Scottish Country Dancers: http://www.skagitscd.org

Reach me by ICQ! My ICQ# is 34465298

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